7x^2+4x-4320=0

Solution for 7x^2+4x-4320=0 equation:

7x^2+4x-4320=0

a = 7; b = 4; c = -4320;
Δ = b2-4ac
Δ = 42-4·7·(-4320)
Δ = 120976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{120976}=\sqrt{16*7561}=\sqrt{16}*\sqrt{7561}=4\sqrt{7561}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{7561}}{2*7}=\frac{-4-4\sqrt{7561}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{7561}}{2*7}=\frac{-4+4\sqrt{7561}}{14}
$